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61.800=6400x-18x^2-400
We move all terms to the left:
61.800-(6400x-18x^2-400)=0
We add all the numbers together, and all the variables
-(6400x-18x^2-400)+61.8=0
We get rid of parentheses
18x^2-6400x+400+61.8=0
We add all the numbers together, and all the variables
18x^2-6400x+461.8=0
a = 18; b = -6400; c = +461.8;
Δ = b2-4ac
Δ = -64002-4·18·461.8
Δ = 40926750.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6400)-\sqrt{40926750.4}}{2*18}=\frac{6400-\sqrt{40926750.4}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6400)+\sqrt{40926750.4}}{2*18}=\frac{6400+\sqrt{40926750.4}}{36} $
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